Question

compute the heat generated while transfering 96000 coulomb of charge in one hour through a potential difference of 50v?​

Answer 1

Answer:

Charge (Q) = 96000 C

Time (t) = 1hr = 60 x 60 = 3600 s

Potential difference (V) = 50 V

Let us calculate current (I)

I = Q/t

I = (96000)/(3600)

I = (80/3) A

Let us calculate the quantity of heat generated by using the formula

H = V × I × t

H = 50 × (80/3) × 3600

H = 4.8 × 106 J

Therefore, the heat generated is 4.8 x 106 J.

Answer 2

Answer:

$4.8 \times {10}^{6}$J

Explanation:

Charge (Q) = 96000 C

Time (t) = 1hr = 60 x 60 = 3600 s

Potential difference (V) = 50 V

Let us calculate current (I)

I = Q/t

I = (96000)/(3600)

I = (80/3) A

Let us calculate the quantity of heat generated by using the formula

H = V × I × t

H = 50 × (80/3) × 3600

H = 4.8 × ${10}^{6}$ J

Therefore, the heat generated is

$4.8 \times {10}^{6}$J.