Question

COMPUTE THE HEAT GENERATED WHILE TRANSFERRIN 96000 COULOMBS OF CHARGE IN ONE HOURS THROUGH A POTENTIAL DIFFERENCE OF 50V .( current I = Q/T )

Answer 1

Solution:Given Charge, Q = 96000C

Time, t= 1hr = 60 x 60= 3600s

Potential difference, V= 50volts

Now we know that H= VIt

so we have to calculate I first

As I= Q/t

∴ I = 96000/3600 = 80/3 A

Therefore, the heat generated is 4.8 x 106 J
hope this helps you❤️❤️

Answer 2

________HEY SISTA!!!!! ___________
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» AS WE KNOW THAT :-

=> H = VIt

_______

Here :-

=> V = voltage = 50 V

=> t = 1 h = 3600 s

_______________

THEN,

» AMOUNT OF CURRENT :-

=> I = (Amount of charger)/(time)

=> I = 96000/3600 = 80/3 A

-__________________

And

=> H = 50×3600×80/3 = 4.8×10^6 J

» Therefore, the heat generated "4.8×10^6 J"

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