Question

compute the heat generated while transferring 9600 coulomb of charge in two hours through a potential difference of 40 v.​

Answer 1

Given

• Charge (Q) = 9600
• Time = 2hr = 2 × 60 × 60 = 7200s
• Potential Diffrence (V) = 40 volt

To Find

• Heat generated

Formula

★ H = vit

Solution

i = Q/t

•°•

⟹ H = v×Q×t/t

⟹ H = vQ

⟹ H = 40 × 9600

⟹ H = 384,000 Joule

Answer

heat transfered is 384000 Joule