Question

Compute the heat generated while transferring 96000 coloumb of charge in two hrs. through a potential difference of 40 v

Answer 1

H=I^2RT

V=IR

40= 96000/2×R. (I= 96000/2= 48000

80/96000=R

1/1200= R

H= 48000^2 × 1/1200×2

H = 3840000 in hrs

H= 3840000/3600

H=1066.6 in second