Compute the heat generated while transferring 96000 coulomb of charge
in one hour through a potential difference of 50 V.
An electrie iron of resistance 20 a takes a current of 5 A. Calculate the
heat developed in 50 a.
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Given charge Q = 96000 coulomb.
time = 1hr = 60 * 60 = 3600s.
Potential difference {V} = 50v
According to formula: H= VIT -(i)
Also I = Q/T
∴I = 96000/3600 =80/3= Ampere
putting value of I = 80/3 Ampere in (i)
H=50 X 80/3 X 60 X 60 = 4.8 X 10²×³joule
Heat is generated that is 4.8 X 10²×³ joule
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