Math, asked by neertomar2011, 1 year ago

Compute the heat generated while transferring 96000 coulomb of charge in two hours through a potential difference of 40 v

Answers

Answered by mayankbarnwal
2

Answer:

3.84 Mega Joules

Step-by-step explanation:

W = VQ

But the work done is dissipated entirely in the form of heat.

.°. H = VQ

H = 40 × 96000

H = 3840000 J = 3.84 × 10^6 J

H = 3.84 MJ (Mega Joules)

Answered by samriddhsaxena
1

Answer:

This was the simplest method but if you want to do it by the other way then find the Current (I) first and then apply the formula H = V×I×T..

The answer would come same..

Hope it helps you.

Mark Brainliest if found helpful.

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