Question

Compute the heat generated while transferring 96000 coulomb of charge in one hour through a potential difference of 50 V.
pls answer ​

Answer 1

Answer:

Answer:

The “amount of heat” generated is 4.8\times10^6 J4.8×10

6

J

Solution:

Given

Charge given, Q = 96000 C

Time given (t) = 1 hour =60 × 60 s = 3600 s

Voltage (V) = 50 V

We know that, current can be found out by using the formula,

\begin{gathered}\begin{array} { c } { I = \frac { Q } { t } } \\\\ { I = \frac { 96000 } { 3600 } = \frac { 80 } { 3 } A } \end{array}\end{gathered}

I=

t

Q

I=

3600

96000

=

3

80

A

Amount of heat generated can be found out using the formula,

\begin{gathered}\begin{array} { c } { \mathbf { H } = \mathbf { V I t } } \\\\ { = 50 \times \frac { 80 } { 3 } \times 3600 } \\\\ { = 4800000 \mathrm { J } } \\\\ { = 4.8 \times 10 ^ { 6 } \mathrm { J } } \end{array}\end{gathered}

H=VIt

=50×

3

80

×3600

=4800000J

=4.8×10

6

J

Thus, the “amount of heat” generated is 4.8\times10^6 J4.8×10

6

J