Question

compute the heat generated while transferring 96000 coulomb of charge in one hour through a potential difference of 50v.

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Answer 1

Q=96000 C

t=1 hr=3600seconds

$I = \frac{Q}{T} = \frac{96000}{3600} = \frac{80}{3} A$

V=50 V

Amount of heat generated is

H=VIt

$=50× \frac{80}{3} ×3600$

=4800000 J

Power input by the source is

P=VI

$=50× \frac{80}{3}$

=1333.3W