Question

compute the heat generated while transferring 96000 coulomb of charge in two hours through a potential difference of 40 V. ​

Answer 1

Answer:

96000 ÷ 40 = 28000 is answer

Answer 2

Answer:

Given Charge (Q) =96000C

Time (t)=1hr=60×60=3600s

Potential difference V=50volts

Now we know that H= VIt

So we have to calculate I first

As I=Q/t

∴ I=96000/3600=80/3 A

Now we can calculate the heat generated

H=J

=50×80×1200J

=4800000J

=4.8×106J.