Question

compute the heat generated while transferring 96000 coulomb of charge in hour through a potential difference of 50 volt

Answer 1

Answer:

The “amount of heat” generated is $4.8\times10^6 J$

Solution:

Given  

Charge given, Q = 96000 C

Time given (t)  = 1 hour =60 × 60 s = 3600 s

Voltage (V) = 50 V

We know that, current can be found out by using the formula,

$\begin{array} { c } { I = \frac { Q } { t } } \\\\ { I = \frac { 96000 } { 3600 } = \frac { 80 } { 3 } A } \end{array}$

Amount of heat generated can be found out using the formula,

$\begin{array} { c } { \mathbf { H } = \mathbf { V I t } } \\\\ { = 50 \times \frac { 80 } { 3 } \times 3600 } \\\\ { = 4800000 \mathrm { J } } \\\\ { = 4.8 \times 10 ^ { 6 } \mathrm { J } } \end{array}$

Thus, the “amount of heat” generated is $4.8\times10^6 J$

Answer 2

Answer:

Explanation:

Given :-

Charge, Q = 96000 C

Time, t = 1 hour = 60 × 60 = 3600 seconds

Potential Difference, V = 50 V

To Find :-

Heat Generated = ???

Formula to be used :-

Heat Generated = Q × V

Solution :-

Putting all the values, we get

⇒ Q × V

⇒ 96000 C  × 50 V

⇒ 96000 × 50 J

⇒ 4.8 × 10¹⁶ J

Hence, the heat generated is 4.8 × 10¹⁶ J.