Question

compute the heat generated while transferring 96000 coulomb of charge in our hour through a potential difference of 50 volts.

Answer 1

Given Charge (Q) =96000C

Time (t)=1hr=60×60=3600s

Potential difference V=50volts

Now we know that H= VIt

So we have to calculate I first

As I=Q/t

∴ I=96000/3600=80/3 A




Answer 2

ANSWER :

COULOMB : The S.I Unit of electric charge.

ELECTRIC CHARGE : There are 2 types of charges positive ( + ve ) and negative ( - ve ).

• Positive charge particles are protons.

• Negative charge particles are electrons.

• A charged body has a tendency to repel another charged body.

POTENTIAL DIFFERENCE : The amount of work done in moving a charge from one point to the another point in an electric circuit.

• Potential difference = work done / charge

• V      = W/Q

• S.I UNIT : Volt

ELECTRIC CURRENT S.I Unit  = Ampere / amp

ELECTRIC RESISTANCE S.I Unit  =  Ohm ( 1 Ω )

1 ohm  = 1 volt / 1 ampere

S.I Unit of ENERGY = Joules

• Charge  =  96000 coulomb

       Time ( t )  =   1 hour = 3600 seconds.

      Potential Difference =   50V

                 Current ( I )     =  Q/T               ( Q = CHARGE AND T = TIME )

                     I                   =  96000 / 3600

                     I                   =  80/3 amp

                     V                 =  I × R                             ( R = Resistance )

           

                    50               =  80/3 × R

  Thus.          R                =  15/8 ohm            

                    Heat             =  I²RT

                                        =  ( 80/3 )² × 15/8 × 3600

                                        = 800 × 6000

                                        =  4800000 Joules.