Question

Compute the heat generated while transferring 96000 coulomb of charge in one hour through a potential difference of 50 V.​

Answer 1

Answer:

mrk as brainlest

Explanation:

Given parameters

Charge (Q) = 96000 C

Time (t) = 1hr = 60 x 60 = 3600 s

Potential difference (V) = 50 V

Let us calculate current (I)

I = Q/t

I = (96000)/(3600)

I = (80/3) A

Let us calculate the quantity of heat generated by using the formula

H = V × I × t

H = 50 × (80/3) × 3600

H = 4.8 × 106 J

Therefore, the heat generated is 4.8 x 106 J.

Answer 2

Answer:

Given,

Q=96000C

P. D=50v

T=1 hr

A/q

I=Q/T

=96000/60x60

96000/3600

=80/3

Now

H=VIT

=50X80/3X3600

=4.8x10^6 Ans