Question

Compute the heat generated while transferring 96000C of charge
in one hour through a potential difference of 50V.
​

Answer 1

Answer:

4.8 *10^8J

Explanation:

Q = 3600s

I= Q/t = 80/3

H= Vit

= 50 * 80/3 * 3600

4.8*10^8 J

Answer 2

Answer:

Given charge Q = 96000 coulomb.

time = 1hr = 60 * 60 = 3600s.

Potential difference {V} = 50v

According to formula: H= VIT -(i)

Also I = Q/T

∴I  = 96000/3600 =80/3= Ampere

putting value of I = 80/3 Ampere in (i)

H=50 X 80/3 X 60 X 60 = 4.8 X 10²×³joule

Heat is generated that is 4.8 X 10²×³ joule