Question

Compute the heat generated while transforming 96000 C of charge in 1 hour through a potential difference of 50 V

Answer 1

Q=96000c

t=3600sec

I=Q/t  ⇒ 96000/3600 = 80/3 A

V=50v

H=VIt

= 50×80/3×3600

=4800000J

Answer 2

Answer:

Given charge Q = 96000 coulomb.

time = 1hr = 60 * 60 = 3600s.

Potential difference {V} = 50v

According to formula: H= VIT -(i)

Also I = Q/T

∴I  = 96000/3600 =80/3= Ampere

putting value of I = 80/3 Ampere in (i)

H=50 X 80/3 X 60 X 60 = 4.8 X 10²×³joule

Heat is generated that is 4.8 X 10²×³ joule