Physics, asked by Veerana4032, 1 year ago

Compute the magnitude and direction of magnetic field at the centre o of the given current carrying bent wire

Answers

Answered by ansh841507
1

Explanation:

Magnetic Field due to Current Carrying Circular Loop

Difficulty Level: At Grade | Created by: CK-12

Add to Library

Magnetic Field Pattern due to a Circular Loop Carrying Current

The magnetic field lines are concentric circles at every point of a current carrying circular loop. The direction of magnetic field of every section of the circular loop can be found by using the right hand thumb rule.

At the centre of the circular loop, The magnetic field lines are straight.

Each segment of circular loop carrying current produces magnetic field lines in the same direction with in the loop.

The direction of magnetic field at the centre of circular coil is perpendicular to the place of the coil. i.e. along the axis of the coil.

Factors affecting the strength of magnetic field

1. The magnitude of magnetic field is directly proportional to the magnitude of current through the loop. i.e.

B∝I

.

2. The magnitude of magnetic field is inversely proportional to the radius of the circular loop. i.e.

B∝1r

.

The following video explains the magnetic field pattern around a circular coil carrying current.

Answered by PoojaBurra
4

The magnitude and direction of magnetic field at centre of current carrying bent wire is μI/4πa And it is directed Into the page for every length element.

  • Let us assume O be the centre of current carrying wire and a be the radius
  • The magnetic field at O due to the current in the straight segments AA′  and BB′  is zero because ds×rˆ=0
  • By applying BIOT-SAVART’S LAW to the segment AB .Each length element ds along path Ac is at the same distance a from O
  • The solution is given clearly in the image go through it for Further clarity
Attachments:
Similar questions