Compute the mass in gram of kcl o3 necessary to produce 67.2 litre of oxygen at stp according to the reaction
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Answer:
245 grams
Explanation:
According to avogadro's law, 1 mole of every substance occupies 22.4 Liters at STP and contains avogadro's number of particles.
According to stoichiometry, 3 moles of are produced from 2 moles of
Thus of are produced from 2 moles of
Mass of
Thus 245 grams of necessary to produce 67.2 liters of oxygen at S. T. P.
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