Question

compute the median for the following data.
PLEASE HELP​

Answer 1

Marks ----------------- C.F ---------- Fr.

140 - 150 ------------- 12 ------------ 12

130 - 140 ------------- 27 ------------ 15

120 - 130 ------------- 60 ----------- 33

110 - 120 -------------- 105 ---------- 45

100 - 120 ------------- 124 ---------- 19

90 - 100 -------------- 141 ----------- 17

80 - 90 -------------- 150 ----------- 9

___________________________

Median =

$l + ( \frac{ \frac{n}{2} - cf}{f} ) \times h$

where,

• L = lower limit of median class
• h = difference between upper limits and lower limits
• f = frequency of median class
• cf = cumulative frq. preceding the median class

________________________

Here,

• n = 150
• n/2 = 75
• median class = (110 - 120)
• f = 45
• h = 10
• L = 110
• cf = 60

___________________

Substituting the values,

Median = 110 + (75 - 60/45)10

= 110 + (15/45)10

= 110 + 150/45

= 110 + 3.3

= 113.3

__________________

Median = 113.3

Answer 2

Answer:

n = 150

n/2 = 75

median class = (110 - 120)

f = 45

h = 10

L = 110

cf = 60

___________________

Substituting the values,

Median = 110 + (75 - 60/45)10

= 110 + (15/45)10

= 110 + 150/45

= 110 + 3.3

= 113.3

__________________

Median = 113.3