Compute the missing frequencies 'F1' and 'F2' in the following data if the mean is 166 9\26 and the sum of observations is 52. Data :-
=>Class frequency
• 140-150. 5
• 150-160. F1
• 160-170. 20
• 170-180. F2
• 180-190. 6
• 190-200. 2
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Concept:
Frequency is the no. of times something occurred
Given:
the mean is 166 9\26 and the sum of observations is 52. Data :-
=>Class frequency
• 140-150. 5
• 150-160. F1
• 160-170. 20
• 170-180. F2
• 180-190. 6
• 190-200. 2
Find:
f1 and f2
Solution:
Sum of observations=52
5+f1+20+f2+6+2=52
f1+f2+33=52
f1+f2=19----------------------(i)
Σfx=-2f₁-25
mean=a+hΣfx/Σf
⇒166 9/26=175+10(-2f₁-25)/52
⇒4325/26-175=-10(2f₁+25)/52
⇒(4325-4550)/26=-10(2f₁+25)/52
⇒-225/26=-10(2f₁+25)/52
⇒45=2f₁+25
⇒f₁=10
f₂+10=19
f₂=9
Therefore,f₁=10 and f₂=9
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