Compute the mode in given data
Class:10-15 15-20 20-25 25-30 30-35 35-40
Frequency:
3
7
16
12
9
5
3
Answers
Answer:
Answer
Size of the itemf
10 – 15
15 - 20
4
8
20 - 25 18
25 - 30
30 – 35
30 20
35 – 40 10
40 – 45
5
45 - 50 2
Modal class is 25 - 30 since it has the
maximum frequency.
Lower limit of the modal class1= 25
Frequency of the modal class f = 30
Frequency of the preceding modal class fi
18
Frequency of the class reducing the modal
class f2 = 20
Class widthc=5
Mod =
1+
= 25+
2f – f1 – fz)
30 18
60 – 18-
20
хс
X 5 = 25+
Modal class is 25 – 30 since it has the
maximum frequency.
Lower limit of the modal class1= 25
Frequency of the modal class f = 30
Frequency of the preceding modal class f1
18
Frequency of the class reducing the modal
class f2 = 20
Class widthc= 5
Mode =1+
= 25+
12 X 5
22
f-f1
2f-f1-f2
30 - 18 60 18 20
60
22
= 25 + 2.73 = 27.73
X c
X 5 = 25 +
30%
= 25+
Mode = 27.73
Answer:
Size of the item f
10−15 4
15−20 8
20−25 18
25−30 30
30−35 20
35−40 10
40−45 5
45−50 2
Modal class is 25−30 since it has the maximum frequency.
Lower limit of the modal class l=25
Frequency of the modal class f=30
Frequency of the preceding modal class f
1
=18
Frequency of the class reducing the modal class f
2
=20
Class width c=5
Mode =l+(
2f−f
1
−f
2
f−f
1
)×c
=25+(
60−18−20
30−18
)×5=25+
22
12×5
=25+
22
60
=25+2.73=27.73
Mode =27.73
Explanation:
hope it helps you dear