Question

Compute the natural logarithm of 2, by adding up to n terms in the series
a. 1 - 1/2 + 1/3 - 1/4 + 1/5 -... 1/n where n is a positive integer and input by user

Answer 1

You can have a separate variable, n that you add one to each time, check if it is even with if (n%2 == 0). If that is true, multiply your denominator by -1.

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Answer 2

Natural algorithm of logarithm 2 in C++ language.

As per the given question we have to compute the natural logarithm of 2, by adding up to n terms in the series.

a) 1 - 1/2 + 1/3 - 1/4 + 1/5 -... 1/n where n is a positive integer and input by user.

So, here we have done the programming in C++ language.

# include < iostream >

using namespace std ;

int main ()

{

int i ,n ,sign = -1;

float sum=0;

cout << " Enter the value of n ";

cin >> n;

for( i = 1 ; i < = n ; i++ )

{

 sign *= -1;

 sum += sign * 1.0 / i;

}

cout << " log 2 : " << sum ;

return 0;

}

The Output Is:  

Sample rum 1

Enter the value of n 5

log 2 : 0.783333

Sample run 2

Enter the value of n 10000

log 2 : 0.693091

For more such kind of logarithm questions:

https://brainly.in/question/41400643

https://brainly.in/question/38013487

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