Question

compute the no
.
of atoms present in 200g of N2​

Answer 1

Answer:

8.6028 * 10²⁴ atoms

Explanation:

28 g = 1mol N2

200g = 200/ 28 mol N2

200 g = 200/28 * 6.022*10²³ N2 molecules

200g = 200/28 * 6.022* 10²³ * 2 N atoms

200g = 8.6028 * 10²⁴ atoms

Answer 2

Answer:

8.6028*10 power 24

Explanation:

28gm =1mol N2

200gm=200/28 mol N2

200gm =200/28*6.022*10power23 N2

Molecules

200gm =200/28*6.022*10power23 2N atoms

200gm =8.6028*10power24 atoms