Question

compute the no.of ions present in 11.7g of sodium chloride.​

Answer 1

Answer:

6.02×10²³ molecules = molar mass of that substance

molar mass of NaCl =23+35.5= 58.5 g

then,58.5g NaCl= 6.02×10²³ molecules

now for 11.7 g,

÷ 58.5 in both sides,

58.5/58.5 g NaCl =6.02×10²³/58.5 molecules

1g NaCl = 6.02 ×10²³/58.5 molecules

×11.7 in both sides,

11.7g NaCl = (6.02×10²³/58.5)×11.7 molecules= 1.2×10²³

then no of ions can be find using concept of atomicity

no.of ions=atomicity×no of molecules

atomicity of NaCl= 1na+ and 1cl-

=2

no of.ions of NaCl = 2×1.2×10²³ = 2.4×10²³ ions