Question

compute the number of atoms present in 200g of NH3-​

Answer 1

Answer:

283.24*10^23

Step-by-step explanation:

Mass of NH3 ( W ) = 200g

Molar mass of NH3 ( M ) = 17g

No. of molecules in 200g = 200/17*6.022*10^23

                                           = 70.81*10^23

No. of atoms present in 1 molecule = 4

No. of atoms present in 200g = 4*70.81*10^23

                                                  = 283.24*10^23