Question

Compute the number of Ions present in 11.7 g of sodium chloride.​

Answer 1

Answer:

Given:−

Mass of NaCl =11.7 g

Molar mass of NaCl = 23+35=58g/mol

\huge\orange{Required:- }Required:−

Number of ions=?

\huge\blue{Solution :- }Solution:−

Moles of NaCl =mass/ molar mass

Moles of NaCl =11.7/58

Moles of NaCl = 0.2mol

Now ........

Moles of NaCl = Number of molecules /Avagadro number

Number of molecules = moles×Avagadro number

Number of molecules =0.2 × 6.023×10^23

Number of molecules of NaCl = 1.2×10^23

Now ......

We know that in one molecule of NaCl 2 ions that is Na+ and Cl_ are present so .......

1.2 ×2 ×10^23

\huge\red{2.4×10^23 Ions }2.4×10

2

3Ions