Question

compute the number of ions present in 5.85 gram of sodium chloride​

Answer 1

Answer:

According to given data,

5.85 g of NaCl=

58.5

5.85

=0.1 moles of NaCl particle

Each NaCl particle contains 2 ions Na

+

and Cl

−

⇒ Total moles of ions =0.1×2 =0.2 moles

No. of ions =0.2×6.022×10

23

=1.2042×10

23

ions

Answer 2

Answer:

number of ions = (5.85/58.5) Avogadro number

= 0.1 x 6.023 x 10^23

= 6.023 x 10^22