Question

compute the number of ions present in 5.85 grams of sodium chloride.please?​

Answer 1

Explanation:

VERY EASY

Molar mass of sodium chloride (NaCl)g <br>58.5g of NaCl has number of ions<br> As,<br>5.85 g of NaCl has number of ions<br>

Answer 2

Answer:

Molar mass of Sodium chloride (NaCl)=23+35.5=58.5

=> 58.5 g of NaCl has number of ions =$6.02 \times {10}^{23} \times 2$

As,.

$</em></strong><strong><em>NaCl</em></strong><strong><em> --------> {</em></strong><strong><em>N</em></strong><strong><em>a}^{ + } + {</em></strong><strong><em>C</em></strong><strong><em>l}^{ - }$

5.85 g of NaCl has number of ions=

$\frac{6.022 \times {10}^{23} \times 2 \times 5.85 }{58.5}$

$= 12.044 \times {10}^{22}$

$= 1.2044 \times {10}^{23}$

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