compute the number of ions present in 5.85g of sodium chloride
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No. Of moles = 5.85/58.5 = 0.1
No of ions will be of both Na that is Na + and Cl-
= 0.1 × 2 × 6.022 × 10^23
= 1.2044 × 10^23 ions.
Hope it helps!
No of ions will be of both Na that is Na + and Cl-
= 0.1 × 2 × 6.022 × 10^23
= 1.2044 × 10^23 ions.
Hope it helps!
Jhani:
Pls mark it best if understood.
m sorry but its incorrect
What's the right ans,?
its 6.022 × 10^22 of Na+ ions and 6.022 × 10^22 of Cl- ions.
Yeah the same
dude its not the same...
I gave ans in total of both
yeah!
Okay
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