Compute the number of sodium ions present in 5.85g of sodium chloride. (Atomic mass of
sodium =23u and of chorine =35.5u), No=6.022X1023 per mole
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The total atomic mass of Sodium Chloride is :
35.5 + 23 = 58.5 g
From the given mass the mass of Sodium is :
23/58.5 × 5.85 = 2.3 g
The moles of Sodium are :
Moles = mass / Atomic mass.
Moles = 2.3/23 = 0.1 moles
Now ,
1 mole = 6.022 × 10²³ ions
The number of Sodium ions in 5.85 g Sodium Chloride is thus :
0.1 × 6.022 × 10²³ = 6.022 × 10²² Ions
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