compute the rotational kinetic energy of a 2kg wheelrotating at 6 revolutions per second if the radius of gyration of the wheel is 0.22m.
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Mass = 2kg
Speed = 6 revolution per sec
= 6 × 2πr /sec
= 12×(22/7)×0.22
= 8.29 m/s
K.E = (1/2)mv^2
= (1/2) × 2 × (8.29)^2
= 68.72 J
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Speed = 6 revolution per sec
= 6 × 2πr /sec
= 12×(22/7)×0.22
= 8.29 m/s
K.E = (1/2)mv^2
= (1/2) × 2 × (8.29)^2
= 68.72 J
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