Compute the surface area of the sphere S : (x ^ 2) + y ^ 2 + z ^ 2 = a ^ 2 using surface integral.
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Step-by-step explanation:
How would you calculate the surface area of the portion of the sphere x2+y2+z2=16zx2+y2+z2=16z that lies within the paraboloid z=x2+y2z=x2+y2.
Points common to the sphere and paraboloid satisfy the equation z+z2=16zz+z2=16z, so there we have either z = 0 or z = 15. The former corresponds to the origin (0, 0, 0) which lies in both surfaces where they both have z = 0 as a tangent plane.
However I am not sure how to continue. Could anyone please guide me through how you would attempt this question? thank you
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