Math, asked by kieratkaur, 1 month ago

Compute the value of 9x2 + 4y2 if xy = 6 and 3x + 2y = 12.​

Answers

Answered by AbhinavRocks10
8

Given:

⇒ Compute the value: 9x² + 4y² if xy = 6 and 3x + 2y = 12.

Calculations:

We know that, the give equation is:

 \sf 3x + 2y = 123x+2y=12

We have to square both the sides:

 \sf 3x + 2y^2 = 12^23x+2y

\sf 9x^2 + 12xy + 4y^2 = 1449x

 \sf 9x^2 + 4y^2 = 144 - 12xy^9x

Taking, (xy = 6):

\sf 9x^2 + 4y^2 = 144 - 729x

 {\sf{\underline{\boxed{\red{\sf{ 9x2 + 4y2 = 72}}}}}}

This is the required answer:

Answered by Anonymous
4

⇒ Compute the value: 9x² + 4y² if xy = 6 and 3x + 2y = 12.

Calculations:

We know that, the give equation is:

⇒\sf 3x + 2y = 123x+2y=123x+2y=123x+2y=12

We have to square both the sides:

⇒\sf 3x + 2y^2 = 12^23x+2y3x+2y²

=12² 3x+2y

\sf 9x^2 + 12xy + 4y^2 = 1449x9x² +12xy+4y²

=1449x

9x^2 + 4y^2 = 144 - 12xy^9x9x²+4y²

=144−12xy9x

Taking, (xy = 6):

⇒9x^2 + 4y^2 = 144 - 729x9x²+4y²

=144−729x

⇒{\sf{\underline{\boxed{\red{\sf{ 9x2 + 4y2 = 72}}}}}} </p><p>9x2+4y2=72

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