compute the value of 9x²+4y² .If xy = 6 and 3x + 2y = 12.
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3x+2y=12=>(3x+2y)
2
=12
2
=>9x
2
+4y
2
+12xy=144
= > 9 {x}^{2} + 4 {y}^{2} + 12(6) = 144 = > 9 {x}^{2} + 4 {y}^{2} = 144 - 72 = 72=>9x
2
+4y
2
+12(6)=144=>9x
2
+4y
2
=144−72=72
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