Compute the value of x in each of the following figures .
Explaination please .
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in triangle BCD
120 +DBC=180 linear pair
DBC=180-120
DBC=60
similarly 112+BCD =180 linear pair
BCD =180-112
BCD=68
DBC+BCD+BDC=180 sum of triangle
60+68+x=180
x=180-128
x=52
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From Figure:
EAB and EBC are linear pair.
∠EAB + ∠EBC = 180°
120° + ∠EBC = 180°
∠EBC = 60°
Now,
As we know, using theorem (2) i.e. if a side of triangle is produced, the exterior angle so formed is equal to the sum of corresponding opposite interior angles.
Hence,
∠ACD = ∠A + ∠B
112° = 60° + x
x = 52°
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