Math, asked by mitachokroborti6, 3 days ago

Compute the value of x, in the following figure.​

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Answers

Answered by gurmeetrandawa74
1

Answer:

52°

Step-by-step explanation:

BCD is a straight line BCA and DCA is a liner pair

x + 112°=180

x = 180-112°

x=68°

CAE is a straight line ( like that u can find )

x = 60°

we have 2angle then simply solve

a+b+c =180°

68+60 +x =180°

128+x=180

x =180-128°

x= 52 °

hope it helps u it take to much times

Answered by bhartiaditya650
1

Answer:

In the given figure.

∆ACB+∆ACD=180°( by linear pair)

∆ACB=180°-112°

∆ACB=68°

Now same in ∆EAB+∆CAB=180°( by linear pair)

120°+∆CAB= 180°

∆CAB=180°-120°

∆CAB=60°

we know that sum of angle of triangle is 180°.

∆ABC+∆BCA+∆CAB=180°

∆ABC+68°+60°=180°

∆ABC+128°=180°

∆ABC=180°-128°

∆ABC=52°

Hope you like it my answer.

Have a remarkable day

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