Compute the value of x, in the following figure.
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Answered by
1
Answer:
52°
Step-by-step explanation:
BCD is a straight line BCA and DCA is a liner pair
x + 112°=180
x = 180-112°
x=68°
CAE is a straight line ( like that u can find )
x = 60°
we have 2angle then simply solve
a+b+c =180°
68+60 +x =180°
128+x=180
x =180-128°
x= 52 °
hope it helps u it take to much times
Answered by
1
Answer:
In the given figure.
∆ACB+∆ACD=180°( by linear pair)
∆ACB=180°-112°
∆ACB=68°
Now same in ∆EAB+∆CAB=180°( by linear pair)
120°+∆CAB= 180°
∆CAB=180°-120°
∆CAB=60°
we know that sum of angle of triangle is 180°.
∆ABC+∆BCA+∆CAB=180°
∆ABC+68°+60°=180°
∆ABC+128°=180°
∆ABC=180°-128°
∆ABC=52°
Hope you like it my answer.
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