Question

Compute the volume of a cone of base radius 5cm and height 12cm.​

Answer 1

Radius of base of cone = 5 cm

Height of cone = 12 cm

We know that :-

$\boxed{ \rm \large Volume \: \: of \: \: cone = \frac{1}{3} \times \pi \times {r}^{2} \times h } \\ \\ \rm \: where \: \: r \: = radius \: and \: h \: = height \\ \\ \rm \: value \: of \: \pi = 3.14$

$\rm \longrightarrow \large Volume \: \: of \: \: cone = \dfrac{1}{3} \times 3.14 \times {(5)}^{2} \times 12 \\ \\ \\ \rm \longrightarrow \large Volume \: \: of \: \: cone = \dfrac{1}{3} \times \frac{314}{100} \times 5 \times 5 \times 12\\ \\ \\ \rm \longrightarrow \large Volume \: \: of \: \: cone = \dfrac{1}{1} \times \frac{314}{1} \times 1 \times 1 \times 1\\ \\ \\ \rm \longrightarrow \large Volume \: \: of \: \: cone = 314 \: {cm}^{3}$

Answer :- 314 cm³

Learn more :

Volume of cylinder = πr²h

T.S.A of cylinder = 2πrh + 2πr²

Volume of cone = ⅓ πr²h

C.S.A of cone = πrl

T.S.A of cone = πrl + πr²

Volume of cuboid = l × b × h

C.S.A of cuboid = 2(l + b)h

T.S.A of cuboid = 2(lb + bh + lh)

C.S.A of cube = 4a²

T.S.A of cube = 6a²

Volume of cube = a³

Volume of sphere = (4/3)πr³

Surface area of sphere = 4πr²

Volume of hemisphere = ⅔ πr³

C.S.A of hemisphere = 2πr²

T.S.A of hemisphere = 3πr²

Answer 2

Answer :- 314 cm³

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