Compute the zeroes of the polynomial 4x 2 – 4x – 8. Also, establish a relationship between the
zeroes and coefficients.
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4x 2 – 4x – 8
4x^2-8x+4x-8
4x(x-2)+4(x-2)
4x-4=0. x-2=0
4x=4. x=2
x=4/4. x=2
x=1. x=2
1,2are the zeroes of the polynomial 4x 2 – 4x – 8
Relationship between zeroes and coefficients
Sum of zeroes=-(coefficient of x)/coefficient of x^2=-(-4)/4=4/4=1
Product of zeroes=constant term/coefficient of x^2=-8/4=-2
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- The zeroes of the polynomial 4x² – 4x – 8.
- Find the zeroes and co-efficent ...?
Hence, the value of zeroes is -1 and 2.
The equation is in the form of:-
⟹ 4x² - 4x - 8 = 0
- a = 4
- b = -4
- c = -8
Verified
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