Question

compute the zeros of the polynomial 4 x square - 4 x minus 8 also establish the relationship between the zeros and its coefficient....

Pls answer it in steps ​

Answer 1

Answer:

Step-by-step explanation:

Answer:

step 1:   $4x^{2}-4x-8=0$..................(1)

step2:   $4x^{2}-8x+4x-8=0$

step3:   $4x(x-2)+4(x-2)=0$

step4:   $(x-2) (4x+4)=0$

step5:  zeros are:  $\alpha =2, \beta= -1$

from the equation(1):  $a= 4, b= -4, c= 8$

relationship between the zeros and its coefficient:

$\alpha +\beta = \frac{-b}{a}$ ............(i)                      $\alpha$lpha x beta = c/a.............(ii)

$\alpha +\beta$ = 2-1=1                                  alpha x beta = 2 x (-1) =-2

-b/a = -(-4)/4 =1                              c/a= 8/4 = 2

LHS=RHS                                       LHS=RHS

Answer 2

go through this attachment