Math, asked by tdrnp5246, 1 day ago

compute z=(5+i)/(3-i)+(2)/(1-3i)​

Answers

Answered by rammohanvegi
2

Answer:

=17÷10+(7÷5)i

Step-by-step explanation:

z=(5+i)/(3-i)+2/(1-3i)

=[(5+i)(1-3i)+2(3-i)]÷(3-i)(1-3i)

=[5-15i+i-3i^2+6-2i]÷3-9i-i+3i^2

(i^2=-1)

=[5-17i+3+6]÷3-3-10i

=[14-17i]÷-10i

=-[17i-14]÷-10i

=[17i-14]÷10i

=[17i+14i^2]÷10i

=17i÷10i+14i^2÷10i

=17÷10+(7÷5)i

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