compute z=(5+i)/(3-i)+(2)/(1-3i)
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Answer:
=17÷10+(7÷5)i
Step-by-step explanation:
z=(5+i)/(3-i)+2/(1-3i)
=[(5+i)(1-3i)+2(3-i)]÷(3-i)(1-3i)
=[5-15i+i-3i^2+6-2i]÷3-9i-i+3i^2
(i^2=-1)
=[5-17i+3+6]÷3-3-10i
=[14-17i]÷-10i
=-[17i-14]÷-10i
=[17i-14]÷10i
=[17i+14i^2]÷10i
=17i÷10i+14i^2÷10i
=17÷10+(7÷5)i
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