Question

computer the heat generated while transforms 96000 coulomb of charge in oe hour through a potential differeence of 50v​

Answer 1

Answer:

Q = 96000C

t = 1 hr. = (60 x 60)s = 3600s

I = Q/t = 96000/3600 = 80/3 A

V = 50 V

Amount of heat generated is :-

H = VIt

   = 50 x 80/3 x 3600

   = 4800000 J

   = 4.8 x 10^6 J

Answer 2

Answer:

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