Question

Con starts from rest Attains a velocity of 72kmph in 6sec Calucalate
its acceleration​

Answer 1

Given,
Initial velocity=u=0m/s

Final velocity=V=72km/h

Time=5min

We will convert minutes into hours.
=560h=112h

We have to find out acceleration:
We will denote acceleration by a and distance travelled by s.

Formula used:
a=v−ut⇒a=72−0112⇒a=72×12=864km/h2
a
=
v
−
u
t
⇒
a
=
72
−
0
1
12
⇒
a
=
72
×
12
=
864
k
m
/
h
2

Hence the acceleration is 864km/h2
864
k
m
/
h
2
.

Now, the distance travelled by train:
Formula used:
s=ut+12at2=0×112+12(864)(112)2=12×864×1144=3km
s
=
u
t
+
1
2
a
t
2
=
0
×
1
12
+
1
2
(
864
)
(
1
12
)
2
=
1
2
×
864
×
1
144
=
3
k
m

Hence for 5sec this the aceleration if have given hint to you
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