Question

concave mirror...
focal length is -60cm
h2=-15cm
v=30cm
find magnification= ?
find h1= ?
find u= ? ​

Answer 1

Answer:

Height of image (h2) =?

Height of object (h1) = 5cm

Focal length of mirror(f)=-15cm

Object distance (u)=--20cm

Image distance(v)=?

Now we will apply mirror formulae

1/f=1/v+1/u

-1/15=1/v-1/20

shifting -1/20 to r.h.s

1/20-1/15=1/v

1/v=-1/60

v=-60

Therefore image will be formed at 60 cm in front of mirror

Now, we will calculate magnification.

Since we have two formulas for magnification w will use both the formulas to calculate height of the image.

magnification(m)=-v/u=-(-60/-20)=-3

magnification(m)=h2/h1

                   -3=h2/5

                    -15=h2

                     h2=-15

Therefore size of image will be 12cm in size/height and since size is in negative image will be formed below principal axis.

Explanation:

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Answer 2

Answer:

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