Concentrated aqueous sulphuric acid is 98%h2so4 and has density 1.80gml-1 molarity is
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Concentrated aqueous sulphuric acid is 98% H2SO4 (w/v) and has a density of 1.80 . gmL^-1 . find molarity of solution
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santy2
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Molarity = moles of substance
volume in liters
moles of H2SO4 = mass/ molar mass
denisty = 1.8g/ml(that is 1800g/L)
mass of H2SO4 98% of 1800= 1764g(this is mass of H2SO4 in 1L)
molar mass= 2+32+64 = 98
moles = mass/molar mass = 1764/98
= 18 moles
Therefore in !liter of H2SO4 molarity= moles/volume in liters= 18/1L
= 18M
Molarity =18M
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You have asked the incomplete question. The question is ' Volume of acid required to make 1L of 0.1M H2SO4 is __________ .
Here's your answer:
Concentrated aqueous sulphuric acid = 98% by weight means 98 gm. H2SO4 in 100 gm. solution.
Number of moles = 98 / 98 = 1.
Density = 1.8 g/L
Volume of the solution = Mass of solution / Density = 100 / 1.8 = 55.55 mL = 0.055L.
We know that,
=
18 * V1 = 0.1 * 1000
By solving, we get, V1 = 5.55 mL.
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