Question

Concentrated hcl is 38 by mass what is the molarity of the solution

Answer 1

Explanation:

uestion 1:

H

C

l

(

38

%

)

=

(

38

g

H

C

l

100

g

Soln

)

=

(

?

moles

HCl

1.0

Liter

Solution

)

=> Moles of HCl in 38 grams =

⎛

⎜

⎜

⎝

38

g

H

C

l

36

(

g

mol

)

⎞

⎟

⎟

⎠

=

1.06

mole

H

C

l

=> Volume of Solution (Liters) containing 1.06 mole of HCl

=

100

g

H

C

l

(

38

%

)

1.19

(

g

ml

)

=

84.03

m

l

H

C

l

(

38

%

)

=

0.084

L

H

C

l

(

38

%

)

=> Molarity HCl(38%) =

1.06

mole

HCl

0.084

L

HCl

Conc

=

12.62

M

o

l

a

r

H

C

l

(

a

q

)