Question

Concentrated laboratory ammonia, NH3, is 14.8 M and density of 0.898 g/mL. What is the molality of the solution of ammonia?

Answer 1

Answer:

22.896m

Explanation:

there is 1L solution

density of solution =0.898g/ml

1g/ml=1000g/L=1000×0.898=898g/L

d=m/v=898=m/1 = 898g

14.8M solution

14.8mol of ammonia is present in 1L solution

14.8=mass/17

mass of ammonia =17×14.8=251.6g

molarity=moles of solute/ mass of solvent in kg

mass of solute=251.6g

mass of solution=898g

mass of solvent=898-251.6=646.4g

moles of solute=14.8mol

mass od solvent =646.4/1000kg

molarity=14.8/646.4/1000

=14.8×1000/646.4

=14.8×1000×10/6464

=148000/6464=22.896m