Question

Concentrated nitric acid in laboratory work is 68% nitric acid by mass in aqueous solution. What should be the molarity of such a sample of acid if density of solution is 1.504 g ml^-1 ?

Answer 1

Molarity (M) = 1000 / Volume of solution in mL
                    = (Wb / Mb) × 1000 / (Mass of solution/Density of solution in g mL^-1)
                    = 68/63 × 1000/100/1.504
                    = 68×1.504×10/ 63
                    = 16.23 mol L^-1

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