Concentrated nitric acid used in laboratory work is 68% nitric acid by mass in the aqua solution what should be the molarity of such sample of as if the density of the solution is 1.4
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Letass of hno3 = 68 g
Mass of solution = 100g
Density of solution = 1.4 g/ml
Volume of solution = 100/1.4 = 71.4ml
Molar mass of hno3 = 68
Molarity = (mass of solute
*1000)/ (molar mass of hno3 *Vml)
Molarity = 68*1000/63*71.4
=68000/4498.2
=15.11M
Hope u get that
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