concentrated sulphuric acid has density 1.9g/ml and is 99% h2so4 by weight calculate the molality of the sulphuric acid in the acid
Answers
Molar mass of sulfuric acid=98g/mole
Mass of sulfuric acid in 100 g of solution = 99g
Mass of water in 100 g of solution =1g = 0.001 kg
Number of moles of sulfuric acid in 100 g of solution = 99/98 =1.01 moles
Molality = number of moles of solute/ mass of solvent in kg
= 1.01/0.001
=1010 m
Answer: The molarity of the solution comes out to be 19.19 M.
Explanation:
We are given:
99% m/m . This means that 99 grams of sulfuric acid is present in 100 grams of solution.
Density of solution = 1.9 g/mL
To calculate the volume of the solution, we use the equation:
Density of solution = 1.9 g/mL
Mass of solution = 100 g
Putting values in above equation, we get:
To calculate the molarity of a solution, we use the equation:
Given mass of sulfuric acid = 99 g
Molar mass of sulfuric acid = 98g/mol
Volume of solution = 52.63 mL
Putting values in above equation, we get:
Hence, the molarity of the solution comes out to be 19.19 M.