Question

Concentration of glucose in normal blood is approximately 90 mg per 100 ml . what is the molarity of the glucose solution in blood ​

Answer 1

Answer:

0.005M

Explanation:

Molarity=W↓2×1000

M↓2×volume in ml

M=90×10^-3×1000\18×100ml

=0.005ml

Answer 2

Answer: 0.005 M

Explanation:

Molarity of a solution is defined as the number of moles of solute dissolved per Liter of the solution.

$Molarity=\frac{n\times 1000}{V_s}$

where,

n= moles of solute

$V_s$ = volume of solution in ml

Mass of glucose = 90 mg = 0.09 g

Moles of glucose =[tex]\frac{mass}{\text {molar mass }}=$\frac{0.09}{180g/mol}=0.0005moles$

Volume of solution = 100 mL

Molarity of glucose =$\frac{0.0005\times 1000}{100}=0.005M$

Thus molarity of the glucose solution in blood ​is 0.005 M