concentration of glucose solution which is isotonic to 6 gram per litre of urea solution
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π = CRT
if the temperature is constant concentration of both the solution are equal
so = 6g/ltr
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Given:
The concentration of urea = 6 gm/L
To Find:
The concentration of glucose which is isotonic to the given concentration of urea.
Calculation:
- M.wt of glucose = 180 gm
- M.wt of urea = 60 gm
- The Molarity of urea, M1 = (6 × 1000) / (60 × 1000)
⇒ M1 = 1 / 10 = 0.1 M
- Isotonic solutions are two solutions which have the same osmotic pressure.
⇒ Π (glucose) = Π (urea)
⇒ M2 R T = M1 R T
⇒ M2 = 0.1 M
⇒ No of moles of glucose in 1 litre = 0.1
⇒ Concentration in g/L = 0.1 × 180
⇒ Concentration = 18 gm/L
- So, the concentration of glucose solution which is isotonic to 6 g/L of urea solution is 0.1 M or 18 g/L.
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