Question

concentration of h + ion and oh- minus ion in 10 to the power -
8 M and naoH is respectively

Answer 1

The contribution of OH from water can't be neglected. Asume 10^(-8)M coming from naoh. Applying common ion effect in water, H2O→H ...

Answer 2

Concentration of $H^+$ ion and $OH^-$ is $10^{-6}M$ and $10^{-8}M$ respectively

Explanation:

pH or pOH is the measure of acidity or alkalinity of a solution.

pH is calculated by taking negative logarithm of hydrogen ion concentration.

$pH=-\log [H^+]$

$NaOH\rightarrow Na^++OH^{-}$

According to stoichiometry,  

1 mole of $NaOH$ gives=  1 mole of $OH^-$  

Thus $10^{-8}$ moles of $NaOH$ gives =$\frac{1}{1}\times 10^{-8}=10^{-8}$ moles of $OH^-$  

Putting in the values:

$pOH=-\log[10^-8]$

$pOH=8$

$pH+pOH=14//pOH=14-8=6$

$6=-log[H^+]$

$[H^+]=10^{-6}M$

Thus concentration of $H^+$ ion and $OH^-$ is $10^{-6}M$ and $10^{-8}M$ respectively

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